8x^2-47x-63=0

Solution for 8x^2-47x-63=0 equation:

8x^2-47x-63=0

a = 8; b = -47; c = -63;
Δ = b2-4ac
Δ = -472-4·8·(-63)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-65}{2*8}=\frac{-18}{16}
=-1+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+65}{2*8}=\frac{112}{16}
=7
$